Comment 9 for bug 1109327

With the following testcase, it happens while it shouldn't, according to
the manual:
-----8<-------
#include <stdio.h>
#include <locale.h>

#define STR "²éľÂíɱ²¡¶¾£¬ÖܺèµtÄúµÄ360²»×¨Òµ£¡"

int main(void) {
        char buf[200];
        setlocale(LC_ALL, "");
        printf("%d\n", snprintf(buf, 150, "%.50s", STR));
        return 0;
}
----->8-------

The manual page has this to say:
 About precision:
  An optional precision, in the form of a period (&#8216;.&#8217;) followed by an
  optional decimal digit string.(...) This gives (...) the maximum
  number of characters to be printed from a string for s and S
  conversions.

 About s:
  If no l modifier is present: The const char * argument is expected to
  be a pointer to an array of character type(...)

  If an l modifier is present: The const wchar_t * argument is expected
  to be a pointer to an array of wide characters. Wide characters from
  the array are converted to multibyte characters (...)

There is no "l" modifier, but still, the string goes through the
multibyte conversion code, and fails because the string is invalid
multibyte.

Note, it only works with non UTF-8 locale set in LC_CTYPE or LC_ALL.

This is debian bug http://bugs.debian.org/208308