Binary package hint: maxima
(%i1) residue(%e**(1/z),z,0); (%o1) 0
but according to the laurent series: %e**(1/z) = 1 + 1/z + 1/2z^2 + ... the correct result is 1.
Binary package hint: maxima
(%i1) residue( %e**(1/ z),z,0) ;
(%o1) 0
but according to the laurent series:
%e**(1/z) = 1 + 1/z + 1/2z^2 + ...
the correct result is 1.