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73416ba
(Get the code!)
This is due to choice of the __eq__() method. For "Bar.foo == Foo.id", Reference.__eq__() is executed which generates a correct expression object.
For "Foo.id == Bar.foo", Comparable.__eq__() is executed, which tries to convert Bar.foo (a Reference object) to an integer, which gives a TypeError. Perhaps some of these rich comparison methods should be returning NotImplemented instead? That would allow Reference.__eq__() to have a go in this second case.