Comment 9 for bug 627370

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Oleksandr "Sanja" Byelkin (sanja-byelkin) wrote :

It is the query for better understanding it (the query is the same):

prepare st1 from 'SELECT alias1 . `pk` AS field1
  FROM
    D AS alias1 LEFT OUTER JOIN
    D AS alias2 ON alias1 . `col_int_key` = alias2 . `pk` RIGHT OUTER JOIN
    EE AS alias3 LEFT JOIN
    G AS alias4 ON alias3 . `col_varchar_10_latin1_key` = alias4 . `col_varchar_10_utf8` LEFT JOIN
    D AS alias5 ON alias3 . `col_varchar_10_utf8_key` = alias5 . `col_varchar_10_latin1` ON alias2 . `col_int_key` = alias3 . `pk` LEFT JOIN
    H AS alias6 ON alias5 . `col_int` = alias6 . `col_int_key` LEFT JOIN
    BB AS alias7 RIGHT JOIN
    CC AS alias8 ON alias7 . `col_int_key` = alias8 . `col_int_key` LEFT JOIN
    GG AS alias9 ON alias7 . `col_varchar_1024_latin1` = alias9 . `col_varchar_1024_utf8_key` ON alias4 . `col_varchar_1024_latin1` = alias8 . `col_varchar_1024_utf8`
  WHERE alias9 . `col_int_key` >= alias7 . `pk`
  GROUP BY field1
  HAVING field1 > 6
  ORDER BY field1
  LIMIT 2 OFFSET 3';