Comment 2 for bug 130363

I'll try to do this, but I'm planning to do it differently than it may be done. Rather than finding where the extra call is, I will attempt to make it so that the function can distinguish between its lock on the effect and a different lock that is named the same thing. If it finds a lock is already in place (for the different effect with the same name), it will obey the lock and not run the effect.