Context().import_() raise gpgme.GpgmeError in Python3

[Tojaj]

Hello,
when I try to import a public gpg key in Python3 via Context() method import_ it raises an error:
gpgme.GpgmeError: (7, 32816, 'Invalid argument')
In Python2 it works fine.

Reproducer:
--------------
import gpgme
context = gpgme.Context()
context.import_(open("id_rsa.pub"))

Expected result:
-------------------
No exception raised

Current result:
-----------------
Traceback (most recent call last):
  File "test.py", line 4, in <module>
    context.import_(open("id_rsa.pub"))
gpgme.GpgmeError: (7, 32816, 'Invalid argument')

Note:
I got the same results when I use the StringIO in Python3:

import gpgme
import io
context = gpgme.Context()
stringio = io.StringIO(open("id_rsa.pub").read())
context.import_(stringio)

Am I doing something wrong?

[Tojaj (xtojaj)]

Use of open("id_rsa.pub", 'rb') fix the issue.

But it seems to be little confusing, since my id_rsa.pub is in plaintext and not in binary format.
Moreover this issue is only Python3 specific and Python2 works well even without 'rb' mode specified.

[AndreiM (andrei-macavei89)]

Hi,

It seems that Context.import_() doesn't accept unicode strings and , if I remember correctly, in Python 3 all strings are unicode and after you open the file you get a unicode string as argument for the io.StringIO().

If you want you can use this (it works in Python2):

from StringIO import StringIO

ctx = gpgme.Context()
strio = StringIO(open("id_rsa.pub").read())
ctx.import_(strio)

[Nils Rokita (akasch)]

from io import BytesIO

gpgme.Context()
strio = BytesIO(open("id_rsa.pub", 'rb').read())
ctx.import_(strio)

Works for me. if the key is in a variable one have to encode it:

ctx = gpgme.Context()
result = ctx.import_(BytesIO(keytext.encode('utf-8')))