Comment 10 for bug 929732

> However, I must confess that I may not know how to get table_statistics to recognize v, v2, v3 and v4 as different tables in the output.

I do it like this:

create table v2 like v;
insert into v2 select * from v;
## same for v3, v4

make the different subqueries access the created tables v2, v3, v4.