If a tree was created by objectify.parse, I can't use find() on it, I need to use getroot().find():
>>> from lxml import objectify
>>> from StringIO import StringIO
>>> f = StringIO("<root>data</root>")
>>> tree = objectify.parse(f)
>>> tree.find.__doc__.split('\n')[0]
'find(self, path, namespaces=None)'
>>> tree.find('/root')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "lxml.etree.pyx", line 1944, in lxml.etree._ElementTree.find (src/lxml/lxml.etree.c:45105)
TypeError: find() takes exactly one argument (2 given)
>>> tree.getroot().find.__doc__
'find(self, path)'
>>> tree.getroot().find('/root')
<Element root at 0x7f1655843a50>
>>> tree.getroot().find('/root', None)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: find() takes exactly one argument (2 given)
This testcase is also attached.
Here tree.find('/root') actually translates to tree.getroot().find('/root', None), and apparently tree.getroot().find in the objectify case doesn't take the namespaces argument (it also looks like a dynamically created function). Note that if the tree was created by etree.parse, the code doesn't fail, because in this case tree.getroot().find has the same signature (and proper verbose docstring) as tree.find.
Python : (2, 6, 7, 'final', 0)
lxml.etree : (2, 3, 0, 0)
libxml used : (2, 7, 8)
libxml compiled : (2, 7, 8)
libxslt used : (1, 1, 26)
libxslt compiled : (1, 1, 26)
Hmm, right - I guess ObjectifiedElem