Impossible to configure HTTP server

[Pat Deegan]

I posted to the g00gle group (http://groups.google.com/group/webpy/browse_thread/thread/96280ab488ef784d/1223d4d336fe3be9#1223d4d336fe3be9 ), to no avail so I'm submitting this here.

We really need to get access to the HTTP server prior to entering its listen/serve request loop, so we can customize and configure stuff (e.g. socket timeout). The attached patch (for web.py 0.32) provides an add_servercallback() method to web.application that allows you to do something like:

    ##### snip #####
    class test:
        def GET(self, name):
            return name

    def configure_webserver(server):
        server.timeout = 666

    urls = ("/(.*)", "test")
    app = application(urls, globals())

    app.add_servercallback(configure_webserver)

    # now, the configure_webserver function will be called whenever an HTTP server is instantiated, before it is started.
    ##### snip #####

Feel free to re-organize/rename anything, or ask me to do so, to merge this into the project.

Thanks and regards,
Pat Deegan

[Anand Chitipothu (anandology)]

the configure_webserver function works only for CherryPyWSIServer and not for other types of server. In fact it is not possible to write a function to configure any kind of server.

Here is the work-around: (you need latest web.py code for this)

import web

def create_server(*a, **kw):
    server = web.wsgiserver.CherryPyServer(*a, **kw)
    server.timeout = 666
    return server

web.httpserver.CherryPyServer = create_server

[Anand Chitipothu (anandology)]

importing CheryPyWSGIServer in the beginning of web.httpserver module breaks GAE.

here is the new work-around:

import web

def create_server(server_address, wsgi_app):
    server = web.wsgiserver.CherryPyWSGIServer(server_address, wsgi_app, server_name="localhost")
    server.timeout = 666
    return server

web.httpserver.WSGIServer = create_server