using for with remove skips a job

[Adam Rothschild]

for job in cron:
    print (job)
    cron.remove(job)
cron.write()

This method removes every other job.
Starting crontab

1 1 * * * /usr/bin/echo # comment1
1 2 * * * /usr/bin/echo # comment2
1 3 * * * /usr/bin/echo # comment3
1 4 * * * /usr/bin/echo # comment4
1 5 * * * /usr/bin/echo # comment5
1 6 * * * /usr/bin/echo # comment6
1 7 * * * /usr/bin/echo # comment7
1 8 * * * /usr/bin/echo # comment8
1 9 * * * /usr/bin/echo # comment9
1 10 * * * /usr/bin/echo # comment10

output
1 1 * * * /usr/bin/echo # comment1
1 3 * * * /usr/bin/echo # comment3
1 5 * * * /usr/bin/echo # comment5
1 7 * * * /usr/bin/echo # comment7
1 9 * * * /usr/bin/echo # comment9

crontab after
1 2 * * * /usr/bin/echo # comment2
1 4 * * * /usr/bin/echo # comment4
1 6 * * * /usr/bin/echo # comment6
1 8 * * * /usr/bin/echo # comment8
1 10 * * * /usr/bin/echo # comment10

[Martin Owens (doctormo)]

I've committed a fix for the issue as well as a test that failed before and doesn't now.