QEMU user mode still crashes in multi-thread code.

[Jay Wong]

I compiled the qemu 2.0 release source and find out qemu crashing when emulating multi-thread code in user mode.

I did a little search and found LP:668799 but it is far from now and it is probably not the problem here.

I used program below as the test program:

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>

void *print_message_function( void *ptr );

main()
{
     pthread_t thread1, thread2;
     const char *message1 = "Thread 1";
     const char *message2 = "Thread 2";
     int iret1, iret2;

    /* Create independent threads each of which will execute function */

     iret1 = pthread_create( &thread1, NULL, print_message_function, (void*) message1);
     if(iret1)
     {
         fprintf(stderr,"Error - pthread_create() return code: %d\n",iret1);
         exit(EXIT_FAILURE);
     }

     iret2 = pthread_create( &thread2, NULL, print_message_function, (void*) message2);
     if(iret2)
     {
         fprintf(stderr,"Error - pthread_create() return code: %d\n",iret2);
         exit(EXIT_FAILURE);
     }

     printf("pthread_create() for thread 1 returns: %d\n",iret1);
     printf("pthread_create() for thread 2 returns: %d\n",iret2);

     /* Wait till threads are complete before main continues. Unless we */
     /* wait we run the risk of executing an exit which will terminate */
     /* the process and all threads before the threads have completed. */

     pthread_join( thread1, NULL);
     pthread_join( thread2, NULL);

     exit(EXIT_SUCCESS);
}

void *print_message_function( void *ptr )
{
     char *message;
     message = (char *) ptr;
     printf("%s \n", message);
}

Compiled to i386 and aarch64 object,
and both qemu-i386 and qemu-aarch64 had segmentation faults.

[Erik de Castro Lopo (erikd)]

I think this if bug lp:1098729 which is still open.

[Peter Maydell (pmaydell)]

This test case now works for me, so I think we have resolved the bug that was showing up here.