[check] The context path should been set when start new application

[markshao]

The application which I need to start from sikuli may need to start a internal service from it self. The service need to read the relative path folders from it's own directory.

I try to use the script

App.open(xxx.exe)

to start the application , but when I try to get the service , always got 404 error.

Whether the sikuli should provide the parameters to specify the context path when start the new application via the App.open api

[RaiMan (raimund-hocke)]

Pls. make your request a bit more specific (might be an example helps)

[markshao (mark-shao)]

Append an example

Suppose there is an application name test.exe under the directory A. Whenever the application is started , it start an daemon web service at the same time to provide service for download the html files in the folder HTML under A.

if I directly go the A directory , start the test.exe. The service is ok , I can see the file list in the browser with the host:port

But I use the sikuli code App.open('c:\A\test.exe') , then the service always return 404 not found error.

I guess the problem maybe the context path of the application process. So I start the application from App.open() , the context path of the application process maybe the path where sikuli is located. So the application process could not find HTML folder .

So whether we should set the context path for the application process.

For example the App.open('c:\A\test.exe') should set the context path to be 'C:\A'

Maybe I am wrong , need your advice . Thanks.

[RaiMan (raimund-hocke)]

Thanks, I will add some option for that.