isInSubtreeOf() method is misnamed
Bug #1019093 reported by
Chris Hillery
This bug affects 1 person
| Affects | Status | Importance | Assigned to | Milestone | |
|---|---|---|---|---|---|
| Zorba |
New
|
Medium
|
Matthias Brantner | ||
Bug Description
A->isInSubtreeOf(B) should return true if B is an ancestor of A. However, it actually does the reverse: returns true if B is in a subtree rooted at A. This is backwards. The method should be renamed, perhaps to isAncestorOf().
| Changed in zorba: | |
| importance: | Undecided → Medium |
| assignee: | nobody → Matthias Brantner (matthias-brantner) |
Revision history for this message
| Chris Hillery (ceejatec) wrote | #1 |
| Changed in zorba: | |
| assignee: | Matthias Brantner (matthias-brantner) → Markos Zaharioudakis (markos-za) |
Revision history for this message
| Markos Zaharioudakis (markos-za) wrote | #2 |
| Changed in zorba: | |
| assignee: | Markos Zaharioudakis (markos-za) → Matthias Brantner (matthias-brantner) |
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Probably more Markos's domain.